Many of the terms used in triangle geometry are presented in Eric Weisstein's MathWorld, including topics contributed by Darij Grinberg, Floor Lamoen, and Peter Moses.

A number of terms defined at MathWorld originated in this Glossary, using trilinear coordinates. The need for definitions using barycentric coordinates has led to P. L. Douillet's highly recommended Translation of the Kimberling’s Glossary into barycentrics.

In 2012, links to

Tableswere added to ETC. These tables include many examples of conjugates of various kinds (e.g., aleph, beth, gimel, he, waw, zayin, complementary, and anticomplementary), introduced in C. Kimberling, Collineations, Conjugacies, and Cubics,Forum Geometricorum2 (2002) 21-32. Those definitions are included below.In 2016, an Index of Triangles Referenced in ETC was provided by César Lozada. You can access it here, and also from

Tables.

In this Glossary, points and lines are given in homogeneous coordinates. The coordinates are assumed to be trilinear unless otherwise indicated (as barycentric or polar coordinates), and they are used here to

points, lines, circles, triangle centers, etc. Likewise, zero determinantsdefinecollinearity and concurrence, etc. Consequently, triangle geometry is presented here at a much more general level than a single euclidean triangle. In this treatment, the symbols a,b,c are regarded as algebraic indeterminates or variables, so that points, as functions of a,b,c, are quite different from points in a two-dimensional plane. When (a,b,c) are real numbers restricted by the "triangle inequalities" for sidelengths (i.e., a ≤ b + c, b ≤ c + a, c ≤ a + b), the result is traditional triangle geometry. In favor of the greater generality, in this Glossary, algebraic definitions take precedence over traditional geometric construction-definitions. (For more in this vein, see the definitions of line, point, and symbolic substitution.)defineThe words "defined cyclically" apply after an "A-object" has been defined: if the A-object is F(A,B,C), then the B-object is F(B,C,A), obtained by the cyclic permutation ABC → BCA, and the C-object is, likewise, F(C,A,B). Example: If A' is the point where lines AP and BC meet, and B' and C' are defined cyclically, then B' is where lines BP and CA meet, and C' is where lines CP and AB meet.

## aleph conjugate

Let P = p : q : r and U = u : v : w be points, neither lying on a sideline of ABC. The P-aleph conjugate of U is the pointh(p,q,r,u,v,w) : h(q,r,p,v,w,u) : h(r,p,q,w,u,v),

whereh(p,q,r,u,v,w) = - q ^{2}r^{2}u^{2}+ r^{2}p^{2}v^{2}+ p^{2}q^{2}w^{2}+ (vw + wu + uv)( - q^{2}r^{2}+ r^{2}p^{2}+ p^{2}q^{2}).Let g be the mapping given by

g(x : y : z) = -x/p + y/q + z/r : x/p - y/q + z/r : x/p + y/q - z/r. The P-aleph conjugate of U is "what you do to g(X) to make g(X

^{ -1}) when f(X) = U." (Hyacinthos #4111, Oct. 11, 2001.)

## anticevian triangle

Let P be a point not on a sideline of ABC. Let A' = AP∩BC. Let A" be the harmonic conjugate of P with respect to A and A'. Define B" and C" cyclically. Triangle A"B"C" is the anticevian triangle of triangle ABC. (The lines AP, BP, CP are theceviansof P, and A'B'C', thecevian triangleof P.)If P = p : q : r, then A" = - p : q : r, B" = p : - q : r, C" = p : q : - r. Examples of anticevian triangles

excentral; P = incenter = X(1) = 1 : 1 : 1

anticomplementary; P = centroid = X(2) = 1/a : 1/b : 1/c

tangential; P = symmedian point = X(6) = a : b : c## anticomplement

If points P and Q are collinear with the centroid G, then P is the anticomplement of Q if G trisects segment PQ and is closer to Q than to P. See alsocomplement. (According to Court, p. 297, the termanticomplementary pointdates from 1886.)

## anticomplementary triangle

Let L(A) be the line through vertex A parallel to side BC, and define L(B) and L(C) cyclically. Let A' = L(B)∩L(C), and define B' and C' cyclically. Then A'B'C' is the anticomplementary triangle of ABC. (Efforts to replace this name have encountered the fact that A' is the anticomplement of A.)

## anticomplementary conjugate

Let P = p : q : r and U = u : v : w be points, neither lying on a sideline of ABC. The P-anticomplementary conjugate of U is the pointh(a,b,c,p,q,r,u,v,w) : h(b,c,a,q,r,p,v,w,u) : h(c,a,b,r,p,q,w,u,v),

whereh(a,b,c,p,q,r,u,v,w) = [b ^{2}/q(au + cw) + c^{2}/r(au + bv) - a^{2}/p(bv + cw)]/a.Let f(X) be the anticomplement of X, given by

f(x : y : z) = (- ax + by + cz)/a : (ax - by + cz)/b : (ax + by - cz)/c, and let k be P-isoconjugation. The P-anticomplementary conjugate of U is "what you do to f(X) to make f(k(X)) when f(X) = U."

If P = incenter, then P-anticomplementary conjugate is shortened to "anticomplementary conjugate."

## antigonal image

Let P = p : q : r (barycentric coordinates) be a point not on a sideline of ABC and not X(4). The antigonal image of P is the point h(P) given by barycentyricsh(a,b,c,p,q,r) : h(b,c,a,q,r,p) : h(c,a,b,r,p,q),

whereh(a,b,c,p,q,r) = p/[(b ^{2}+ c^{2}- a^{2})p^{2}- a^{2}qr + (b^{2}- a^{2})pq + (c^{2}- a^{2})pr].The point h(P) is the isogonal conjugate of the inverse-in-circumcircle of the isogonal conjugate of P. If P lies on the circumcircle then h(P)=X(4); otherwise, h(h(P))=P, so that h(P), in such a case, is called the antigonal conjugate of P. If P lies on the line at infinity, then h(P)=P.

Antigonal pairs of points are discussed in Jan Van Yzeren, "Pairs of Points: Antigonal, Isogonal, and Inverse,"

Mathematics Magazine65 (1992) 339-347.Subsequent developments occur in Hyacinthos, beginning with #7825.

## barycentric image (see homologous images)

## beth conjugate

Let P = p : q : r and U = u : v : w be points, neither lying on a sideline of ABC. The P-beth conjugate of U is the pointh(a,b,c,p,q,r,u,v,w) : h(b,c,a,q,r,p,v,w,u) : h(c,a,b,r,p,q,w,u,v),

whereh(a,b,c,p,q,r,u,v,w) = 2abcp(cos B + cos C)(ua'/p + vb'/q + wc'/r) - (a+b+c)a'b'c'u, where a', b', c' are - a + b + c, a - b + c, a + b - c, respectively. Let f by the mapping given by

f(x : y : z) = p(y + z) : q(z + x) : r(x + y), and let k be the mapping "reflection in the circumcenter." The P-beth conjugate of U is "what you do to f(X) to make

f(k(X)) when f(X) = U." (Hyacinthos #4146, Oct. 26, 2001.)

## bicentric points

Let f(a,b,c) : f(b,c,a) : f(c,a,b) be a point that satisfies (1) in the definition of triangle center, but that |f(a,b,c)| ≠ |f(a,c,b)|. Thenf(a,c,b) : f(b,a,c) : f(c,b,a) and f(a,b,c) : f(b,c,a) : f(c,a,b) are bicentric points, together comprising a

bicentric pair. Example: the Brocard points, c/b : a/c : b/a and b/c : c/a : a/b.

centerSeetriangle center.

## central triangle

Let each of f(a,b,c) and g(a,b,c) be a center function (i.e., as in the definition of triangle center) or the zero function, such that one of these conditions holds:(1) the degree of homogeneity of g equals that of f;Let

(2) f is the zero function and g is not the zero function;

(3) g is the zero function and f is not the zero function.A' = f(a,b,c) : g(b,c,a) : g(c,a,b)Then A'B'C' is the

B' = g(a,b,c) : f(b,c,a) : g(c,a,b)

C' = g(a,b,c) : g(b,c,a) : f(c,a,b).(f,g)-central triangle of type 1. Acentral triangle of type 1is any triangle A'B'C' for which equations (1)-(3) hold for some choice of center functions f and g.Next, suppose f and g are as for type 1 except that g(a,b,c) ≠ g(a,c,b). Let

A' = f(a,b,c) : g(b,c,a) : g(c,b,a)Then A'B'C' is the

B' = g(a,c,b) : f(b,c,a) : g(c,a,b)

C' = g(a,b,c) : g(b,a,c) : f(c,a,b).(f,g)-central triangle of type 2. Acentral triangle of type 2is any triangle A'B'C' for some choice of center function f and function g as described. Note that the coordinates in the definitions can be read as barycentrics without changing the classes of triangles called central, central of type 1, and central of type 2.A form for compact notation for a central triangle is T(f(a,b,c), g(b,c,a)), where the triangle is of type 1 if g(b,c,a ) = g(b,a,c) and of type 2 otherwise; see the preamble to X(3758) in ETC.

Examples: ABC, the medial, orthic, excentral, anticomplementary, and tangential triangles are central of type 1; in fact, if X is a center, then the cevian and anticevian triangles of X are central of type 1. The pedal triangle of X is of type 2 if the triangle is not also a cevian triangle.

## Ceva conjugate

Let P = p : q : r and U = u : v : w be points, neither lying on a sideline of ABC. The P-Ceva conjugate of U is the pointu(- qru + rpv + pqw) : v(qru - rpv + pqw) : w(qru + rpv - pqw), which is the perspector of the cevian triangle of P and the anticevian triangle of U. (See

cevian nestandcross conjugate.)Ceva conjugate and cevapoint are related thus: X = P©U if and only if P = cevapoint(U,X), and in this case, U = P©X.

Let f(x : y : z) = p(y + z) : q(z + x) : r(x + y). The P-Ceva conjugate of U is "what you do to f(X) to make f(X

^{ -1}) when f(X) = U." (Hyacinthos #3966, Sept. 26, 2001.)If you have The Geometer's Sketchpad, you can view CEVA CONJUGATE.

## cevapoint

Let P = p : q : r and U = u : v : w be distinct points, neither lying on a sideline of ABC. The cevapoint of P and U is the point(pv + qu)(pw + ru) : (qw + rv)(qu + pv) : (ru + pw)(rv + qw). Let A"B"C" be the anticevian triangle of U. Let A' =PA"∩BC, and define B' and C' cyclically. The cevapoint of P and U is the perspector, X, of triangles ABC and A'B'C'. Moreover, P is the X-Ceva conjugate of U, and U is the X-Ceva conjugate of P. (See

cevian nestandCeva conjugate.) As a comparison of cevapoint(P,U) and crosspoint(P,U), note that their trilinears can be written as1/(qw + rv) : 1/(ru + pw) : 1/(pv + qu) and 1/qw + 1/rv : 1/ru + 1/pw : 1/pv + 1/qu. If you have The Geometer's Sketchpad, you can view CEVAPOINT.

Floor Van Lamoen contributed the following two constructions of cevapoint(P,U). Let A

_{p}B_{p}C_{p}be the cevian triangle of P, and let A_{u}B_{u}C_{u}be the cevian triangle of U. DefineThen triangle ABC is perspective to both triangles A

A _{pu}= C_{p}A_{u}∩A_{p}B_{u}. . . . . . . . . . . . . . A _{up}= C_{u}A_{p}∩A_{u}B_{p}B _{pu}= A_{p}B_{u}∩B_{p}C_{u}. . . . . . . . . . . . . . B _{up}= A_{u}B_{p}∩B_{u}C_{p}C _{pu}= B_{p}C_{u}∩C_{p}A_{u}. . . . . . . . . . . . . . C _{up}= B_{u}C_{p}∩C_{u}A_{p}_{pu}B_{pu}C_{pu}and A_{up}B_{up}C_{up}, and the perspector in both cases is the cevapoint of P and U. (Received 10/17/2003)Randy Hutson noted that cevapoint(P,U) is given by the following constructions:

* The intersection of tangents at P and U to the bianticevian conic of P and U;

* The crosspoint of P and U wrt both the anticevian triangle of P and anticevian triangle of U;

* The pole of line PU wrt the bianticevian conic of P and U. (Received 7/14/2019)## cevian

Let P be a point not on a sideline of ABC. The lines AP, BP, CP are theceviansof P.

## cevian nest

Let D,E,F be triangles, where F is inscribed in E, and E is inscribed in D. If any two of the three triangles are perspective, then the ordered triple (D,E,F) is a cevian nest. (It is well known that if any two of the three triangles are perspective, then each is perspective to the third; in particular, E is a cevian triangle of D, and F is a cevian triangle of E.)Cevian nests in which one of the triangles is ABC beget three families of conjugates:

Ceva conjugates,cross conjugates,andisoconjugates. See alsocrosspoint.)If you have The Geometer's Sketchpad, you can view CEVIAN NEST.

## cevian triangle

Let P be a point not on a sideline of ABC. Let A' = AP∩BC meet. Define B' and C' cyclically. Triangle A'B'C' is the cevian triangle of triangle ABC.If P = p : q : r, then A' = 0 : q : r, B' = p : 0 : r, C' = p : q : 0. Examples of cevian triangles:

incentral triangle; P = incenter = X(1) = 1 : 1 : 1

medial triangle; P = centroid = X(2) = 1/a : 1/b : 1/c

orthic triangle; P = orthocenter = X(4) = sec A : sec B : sec C

intouch triangle; P = Gergonne point = X(7) = sec^{2}(A/2) : sec^{2}(B/2) : sec^{2}(C/2)

extouch triangle; P = Nagel point = X(8) = csc^{2}(A/2) : csc^{2}(B/2) : csc^{2}(C/2)

## circumperp conjugate

Let P = p : q : r be a point distinct from X(3). The circumperp conjugate of P is the pointf(p,q,r,a,b,c,SA,SB,SC) : f(q,r,p,b,c,a,SB,SC,SA) : f(r,p,q,c,a,b,SC,SA,SB),

wheref(p,q,r,a,b,c,SA,SB,SC) = (-a*(-b*c*SC*SB*p^2+2*r*q*SA^3)-SA*a*b*c*(b^2*q^2+c^2*r^2)+b*((SA+SB)*S^2-2*SA*SB^2)*r*p+c*((SC+SA)*S^2-2*SA*SC^2)*p*q)*a. Let ABC be a triangle and P a point. The perpendicular bisectors of BC, CA, AB intersect the circumcircle at (A

_{1}, A_{2}), (B_{1}, B_{2}), (C_{1}, C_{2}), respectively. Then the circumcircles of PA_{1}A_{2}, PB_{1}B_{2}, PC_{1}C_{2}are coaxial. The other than P point of intersection of these circles is the circumperp conjugate of P, as A_{1}, A_{2}, B_{1}, B_{2}, C_{1}, C_{2}are the vertices of the circumperp triangles. (See preamble just before X(18859))

## cocevian triangle

Let P be a point not on a sideline of ABC, and let A'B'C' be the anticevian triangle of P. Let A" be the harmonic conjugate of A' with respect to B and C, and define B" and C" cyclically. (If P = p : q : r, then A" = 0 : y : - z.). The cocevian triangle of P is the triangle A"B"C". The vertices are collinear and the triangle degenerate. For a discussion, see TCCT, page 200.

## combo

Let P and U be finite points having normalized barycentric coordinates (p,q,r) and (u,v,w). Suppose that f = f(a,b,c) and g = g(a,b,c) are nonzero homogeneous functions having the same degree of homogeneity. Let x = fp + gu, y = fq + gv, z = fr + gw. The (f,g) combo of P and U, denoted by f*P + g*U, is the point X = x : y : z; the normalized barycentric coordinates of X are (kx,ky,kz), where k=1/(x+y+z).The definition of combo readily extends to finite sets of finite points. In particular, the (f,g,h) combo of P = (p,q,r), U = (u,v,w), J = (j,k,m) is given by fp + gu + hj : fq + gv + hk : fr + gw + hm and denoted by f*P + g*U + h*J. Suppose that T is a (central) triangle with vertices A',B',C' given by normalize barycentrics. Then T is represented by a 3x3 matrix with row sums equal to 1. Let NT denote the set of these matrices and let * denote matrix multiplication. Then NT is closed under *. Also, NT is closed under matrix inversion, so that (NT, *) is a group. Once normalized, any central T can be used to produce triangle centers as combos of the form Xcom(nT); see the preambles to X(3663), X(3739), and X(3758) in ETC.

## complement

If points P and U are collinear with the centroid G, then P is the complement of U if G trisects segment PU and is closer to P than to U. See alsoanticomplement. (According to Court, p. 297, the termcomplementary pointdates from 1885.)

## complementary conjugate

Let P = p : q : r and U = u : v : w be points, neither lying on a sideline of ABC. The P-complementary conjugate of U is the pointh(a,b,c,p,q,r,u,v,w) : h(b,c,a,q,r,p,v,w,u) : h(c,a,b,r,p,q,w,u,v),

whereh(a,b,c,p,q,r,u,v,w) = [b ^{2}/q(au - bv + cw) + c^{2}/r(au + bv - cw)]/a.Let f(X) be the complement of X, given by

f(x : y : z) = (bv + cw)/a : (cw + au)/b : (au + bv)/c, and let k be P-isoconjugation. The P-complementary conjugate of U is "what you do to f(X) to make f(k(X)) when f(X) = U."

If P = incenter, then P-complementary conjugate is shortened to "complementary conjugate."

## cross conjugate

Let P = p : q : r and U = u : v : w be distinct points, neither lying on a sideline of ABC. The P-cross conjugate of U is the pointu/(- pvw + qwu + ruv) : v/(pvw - qwu + ruv) : w/(pvw + qwu - ruv). Let A'B'C' be the cevian triangle of U. Let A" be where line PA' crosses line B'C', and define B" and C" cyclically - so that A"B"C" is the cevian triangle (in triangle A'B'C', not ABC) of P. The perspector of triangles ABC and A"B"C" is the P-cross conjugate of U. (See

cevian nest.)As a transformation, P-cross conjugate is an involution; i.e., if PxU = P-cross conjugate of U, then Px(PxU) = U. Properties of cross conjugates arise from those of Ceva conjugates; for, on writing PcU for the P-Ceva conjugate of U,

PxU = (U/P)*(UcP) and PcU = (U/P)*(UxP) where / and * denote trilinear division and multiplication.Cross conjugate and crosspoint are related thus: X = PxU if and only if P = crosspoint(X,U).

If you have The Geometer's Sketchpad, you can view CROSS CONJUGATE.

## crossdifference

Let P = p : q : r and U = u : v : w be distinct points, neither lying on a sideline of ABC. The crossdifference of P and U is the point X defined by trilinearsqw - rv : ru - pw : pv - qu, constructible as the isogonal conjugate of the trilinear pole of the line PU. Thus, U is the crossdifference of P and X, and P is the crossdifference of U and X. In order to see that the crossdifference of P and X is a solution for U of the equation

x : y : z = qw - rv : ru - pw : pv - qu,

note first that this equation implies px + qy + rz = 0. Thus, if u : v : w = qz - ry : rx - pz : py - qx, then

qw - rv = q(py - qx) - r(rx - pz) = - (p^{2}+ q^{2}+ r^{2})x, so that

qw - rv : ru - pw : pv - qu = x : y : z.A point X is the crossdifference of distinct points P and U if and only if the line PU is the trilinear polar of the isogonal conjugate of X. Examples:

X(1) = crossdifference of X(44) and X(513)

X(2) = crossdifference of X(187) and X(512)

X(3) = crossdifference of X(230) and X(231).Let W be the side-triangle of these two triangles: the cevian triangle of the isogonal conjugate of P and the cevian triangle of the isogonal conjugate of U. Then W is perspective to ABC, and the perspector is the crossdifference of P and U; see also crosspoint. (Randy Hutson, April 9, 2016)

## crosspoint

Let P = p : q : r and U = u : v : w be distinct points, neither lying on a sideline of ABC. The crosspoint of P and U is the pointpu(rv + qw) : qv(pw + ru) : rw(qu + pv). This point is introduced in TCCT with the notation C(P,Q). Here, "Q" is replaced by "U", and C(P,U) is abbreviated as X. The construction for X given in TCCT follows. Let A'B'C' be the cevian triangle of P and A"B"C" that of U. Let A''' = AA"∩B'C', and define B''' and C''' cyclically. Then X is the perspector of triangles A'B'C' and A'''B'''C'''. Moreover, U is the X-cross conjugate of P, and P is the X-cross conjugate of U. (See

cevian nestandcross conjugate.) The following properties of X were noted by Jean-Pierre Ehrmann (5/29/03):X = perspector of A'B'C' and the triangle with vertices AU∩B'C', BU∩C'A', CU∩A'B';

X = perspector of A"B"C" and the triangle with vertices AP∩B"C", BP∩C"A", CP∩A"B";

X = the point of concurrence of these three lines:

the line of points AP∩BU and AU∩BP

the line of points BP∩CU and BU∩CP

the line of points CP∩AU and CU∩APFigure 7.3 in TCCT with "Q" replaced by "U" can be used to visualize the nine lines concurring in X.

The lines tangent to the conic {A,B,C,P,U} at P and U intersect in X. (Randy Hutson, September 10, 2012)

Let W be the side-triangle of these two triangles: the cevian triangle of P and the cevian triangle of U. Let W' be the vertex-triangle of the anticevian triangle of P and the anticevian triangle of U. Then W is perspective to W', and the perspector is the crosspoint of P and U; see also crossdifference. (Randy Hutson, April 9, 2016)

If you have The Geometer's Sketchpad, you can view CROSSPOINT.

## crosssum

Let P = p : q : r and U = u : v : w be distinct points, neither lying on a sideline of ABC. The crosssum of P and U is the point X defined by trilinearsqw + rv : ru + pw : pv + qu, constructible as the crosspoint of the isogonal conjugates of P and U. Thus, U is the isogonal conjugate of the X-cross conjugate of the isogonal conjugate of P, and P is the isogonal conjugate of the X-cross conjugate of the isogonal conjugate of U. (Regarding the neologism "crosssum" placed here on 5/28/03, what words in the English language have spellings containing three consecutive identical letters?)

## cubic

A cubic is a curve of degree 3 in a,b,c. For a catalog with sketches, visit Bernard Gibert's site.

## cyclocevian conjugate

Let P = p : q : r be a point not on a sideline of ABC, and let A'B'C' be the cevian triangle of P. The circumcircle of A'B'C' meets line BC in two points: A' and A"; pairs B', B", and C',C" are obtained cyclically. The lines AA", BB", CC" concur in the cyclocevian conjugate of P. Letg(a,b,c) = a/[p(qb + rc)] and f(a,b,c) = bc/[g(b,c,a) + g(c,a,b) - g(a,b,c)]. The cyclocevian conjugate of P is given by

f(a,b,c) : f(b,c,a) : f(c,a,b). In Hyacinthos #6423 (January 24, 2003), Darij Grinberg states nine theorems, of which the last is as follows:

The cyclocevian conjugate of a point is the

isotomic conjugate

of the anticomplement

of the isogonal conjugate

of the complement

of the isotomic conjugate

of the point.If you have The Geometer's Sketchpad, you can view CYCLOCEVIAN CONJUGATE.

## daleth conjugate

Let P = p : q : r and U = u : v : w be points, neither lying on a sideline of ABC. The P-daleth conjugate of U is the pointh(p,q,r,u,v,w) : h(q,r,p,v,w,u) : h(r,p,q,w,u,v),

whereh(p,q,r,u,v,w) = p(y/q - z/r) ^{2}+ x(2x/p - y/q - z/r).

## dual triangle

Let DEF be a triangle in the plane of triangle ABC. Let D' be the isogonal conjugate of the point of intersection of line EF and the line at infinity. Define E' and F' cyclically. The triangle D'E'F' is thedualof DEF. The vertices of D'E'F' lie on the circumcircle, and D'E'F' is similar to DEF. The duality is between the sidelines EF, FD, DE and the points D', E', F', respectively. For example, if E and F remain fixed and D varies, then D' remains fixed, while E'F' varies. (From the preamble to X(2979) in ETC.)

## eigencenter

Let T be a central triangle, and let U(T) be the unary cofactor triangle of T. Then T and U(T) are perspective, and their perspector is the eigencenter of T.Suppose the A-, B-, C- vertices of T are P

_{i}= x_{i}: y_{i}: z_{i}, for i = 1,2,3. Lets = y Let x = st - uv, and define y and z cyclically. Then the eigencenter of T is the point x : y : z._{3}(x_{1}x_{2}+ z_{1}z_{2}) - y_{1}(x_{2}x_{3}+ z_{2}z_{3})t = z

_{1}(x_{2}x_{3}+ y_{2}y_{3}) - z_{2}(x_{1}x_{3}+ y_{1}y_{3})u = z

_{3}(x_{1}x_{2}+ y_{1}y_{2}) - z_{1}(x_{2}x_{3}+ y_{2}y_{3})v = y

_{1}(x_{2}x_{3}+ z_{2}z_{3}) - y_{2}(x_{1}x_{3}+ z_{1}z_{3})

## functional image (see homologous images)

## gimel conjugate

Let P = p : q : r and U = u : v : w be points, neither lying on a sideline of ABC. The P-gimel conjugate of U is the pointh(a,b,c,p,q,r,u,v,w) : h(b,c,a,q,r,p,v,w,u) : h(c,a,b,r,p,q,w,u,v),

whereh(a,b,c,p,q,r,u,v,w) = abc[- (cos A)/p + (cos B)/q + (cos C)/r]S - 8uσ ^{2},where S = (bq + cr)u + (cr + ap)v + (ap + bq)w and σ = area of ABC.

## he conjugate

Let P = p : q : r and U = u : v : w be points, neither lying on a sideline of ABC. The P-he conjugate of U is the pointh(p,q,r,u,v,w) : h(q,r,p,v,w,u) : h(r,p,q,w,u,v),

whereh(p,q,r,u,v,w) = -p(y + z) ^{2}+ q(z + x)^{2}+ r(x + y)^{2}

+ (qr/p)(x + y)(x + z) - (rp/q)(y + z)(y + x) - (pq/r)(z + x)(z + y).

## Hirst inverse

Let P = p : q : r and U = u : v : w be distinct points, neither lying on a sideline of ABC. The P-Hirst inverse of U is the pointqru ^{2}- vwp^{2}: rpv^{2}- wuq^{2}: pqw^{2}- uvr^{2}.Geometrically, this is the point of intersection of the line PU and the polar of U with respect to the conic.

pyz + qzx + rxy = 0. As a transformation, P-Hirst inverse is an involution; i.e., if PhU = P-Hirst inverse of U, then Ph(PhU) = U. Concerning the designation "Hirst inverse," see the information contributed by Gunter Weiss.

## homologous images: similarity image, trilinear image, barycentric image, and functional image

The term

homologousmeanshaving the same relation or relative position to. Let T_{1}and T_{2}be two triangles, and P a point in the plane of triangle T_{1}. The point P' in the plane of triangle T_{2}is aTif P' has the same relation or relative position to T_{1}-to-T_{2}homologous image of P_{2}as P has to T_{1}. However, the words "relation or relative position" are subject to different meanings, as discussed here.If T

_{1}and T_{2}are similar triangles, then P' is theT._{1}-to-T_{2}similarity image of PSuppose that P has trilinears x : y : z wrt T

_{1}. Then theTis the point P' with trilinears x : y : z wrt T_{1}-to-T_{2}trilinear image of P_{2}. This is a non-affine collineation, preserving collinearities, but not ratios of distances between collinear points. Parallel lines do not remain parallel under this mapping, so that points on the line at infinity map to finite points. Circumconics of T_{1}map to circumconics of T_{2}and inconics of T_{1}map to inconics of T_{2}.Suppose that P has barycentrics x : y : z wrt T

_{1}. Then theTis the point P' with barycentrics x : y : z wrt T_{1}-to-T_{2}barycentric image of P_{2}. This is an affine collineation, preserving collinearities as well as ratios of distances between collinear points. Parallel lines remain parallel under this mapping, so that the line at infinity maps to itself. Conics map to conics of the same type (ellipses, including circles, map to ellipses, parabolas to parabolas, hyperbolas to hyperbolas). Circumconics of T_{1}map to circumconics of T_{2}and inconics of T_{1}map to inconics of T_{2}.Let the sidelengths of T

_{1}be denoted a_{1}, b_{1}, c_{1}and the sidelengths of T_{2}be denoted a_{2}, b_{2}, c_{2}. Suppose that P has coordinates f(a_{1},b_{1},c_{1}) : g(b_{1},c_{1},a_{1}) : h(c_{1},a_{1},b_{1}) with respect to T_{1}, where f, g, h either have the same degree of homogeneity, or else one is the zero function and the other two have the same degree of homogeneity. (If P is a center of T_{1}, then f = g = h.) Then theTis the point P' with coordinates f(a_{1}-to-T_{2}-functional image of P_{2},b_{2},c_{2}) : g(b_{2},c_{2},a_{2}) : h(c_{2},a_{2},b_{2}) with respect to T_{2}. Coordinates here can be trilinears or barycentrics, as long as the same system is used for T_{1}and T_{2}. P' serves the same 'function' wrt T_{2}(e.g., centroid, circumcenter, 1st Brocard point, A-vertex of orthic triangle, etc.) as P serves wrt T_{1}. For example, the orthic-to-excentral functional image of X(5) is X(40), since X(5) and X(40) are the respective circumcenters of the orthic and excentral triangles. This is a non-affine collineation, preserving collinearities, but not ratios of distances between collinear points (except where these distance ratios define the point, such as midpoints, reflections, etc.). Parallel lines remain parallel under this mapping, so that the line at infinity maps to itself. Circles map to circles. Other conics map to conics, but not necessarily of the same type (e.g., the MacBeath circumconic of T_{1}may be an ellipse, but maps to the MacBeath circumconic of T_{2}, which may be a hyperbola.) Circumconics of T_{1}map to circumconics of T_{2}and inconics of T_{1}map to inconics of T_{2}.

## isoconjugate

Let P = p : q : r and U = u : v : w be points, neither on a sideline of ABC. The P-isoconjugate of U is the pointqrvw : rpwu : pquv. Examples: the

isogonal conjugateof U is the X(1)-isoconjugate of U, and theisotomic conjugateof U is the X(31)-isoconjugate of U.As suggested by the meaning of the prefix "iso",

P-isoconjugate of U = U-isoconjugate of P. Let A'B'C' be the anticevian triangle of U, and let A"B"C" be the anticevian triangle of P

with respect to A'B'C'. The perspector of A'B'C' and A"B"C" is the U^{ -2}-isoconjugate of P, where U^{ -2}= u^{ -2}: v^{ -2}: w^{ -2}. (Seecevian nest.)The earliest appearance of the term "isoconjugate" in triangle geometry may be its inclusion in this Glossary as early as 1998. Isoconjugates are also discussed in C. Kimberling, "Conjugacies in the plane of a triangle,"

Aequationes Mathematicae63 (2002) 158-167, submitted April 27, 1999, and "Conics associated with a cevian nest,"Forum Geometricorum1 (2001) 141-150.Thereafter the term "isoconjugate" was sometimes used for

reciprocal conjugate, a term defined in this Glossary, with a reference to probable earliest usage.

## isogonal conjugate

Let P = p : q : r be a point not on a sideline of ABC. Let L(A) be the line obtained by reflecting line AP in the internal bisector of angle A. Define L(B) and L(B) cyclically. The lines L(A), L(B), L(C) concur in the isogonal conjugate of P, which has trilinears 1/p : 1/q : 1/r and is denoted by P^{ -1}. Seeisoconjugate.If you have The Geometer's Sketchpad, you can view ISOGONAL CONJUGATE and ISOGONAL CONJUGATE OF A LINE.

## isoscelizer

An isoscelizer is a line perpendicular to an angle bisector. If P is a point, then the A-isoscelizer of P is the line L(P,A) through P perpendicular to the line that bisects vertex angle A; the B- and C- isoscelizers are defined cyclically. Let D and E be the points where L(P,A) meets sidelines AB and AC. Unless D = E = A, the triangle ADE is isosceles.In ETC, there are several triangle centers defined in terms of isoscelizers. These were discovered or invented by Peter Yff, in whose notebooks the word

isoscelizerdates back to 1963.

## isotomic conjugate

Let P = p : q : r be a point not on a sideline of ABC. Let A', B', C' be the points where lines AP, BP, CP meet lines BC, CA, AB, respectively. Reflect A', B', C' about the midpoints of sides BC, CA, AB, respectively, to obtain points A", B", C". Then lines AA", BB", CC" concur in the isotomic conjugate of P, which has trilinears 1/(pa^{2}) : 1/(qb^{2}) : 1/(rc^{2}). Seeisoconjugate.

## line

A line is the set of points x : y : z satisfying the equationf(a,b,c)x + g(a,b,c)y + h(a,b,c)z = 0 for some point f(a,b,c) : g(a,b,c) : h(a,b,c). If this point is a triangle center, then the corresponding line is a

central line.Three lines dx + ey + fz = 0, rx + sy + tz = 0, ux + vy + wz = 0 are concurrent if and only the following determinant equation holds:

See also point. Chapter 5 of TCCT discusses central lines.

## line conjugate

Let P = p : q : r and U = u : v : w be distinct points, neither equal to A, B, or C. The P-line conjugate of U is the pointp(v ^{2}+ w^{2}) - u(qv + rw) : q(w^{2}+ u^{2}) - v(rw + pu) : r(u^{2}+ v^{2}) - w(pu + qv),or, equivalently,

hp - ku : hq - kv : hr - kw, where h = u

^{2}+ v^{2}+ w^{2}and k = pu + qv + rw.This is the point of intersection of line PU and the trilinear polar of the isogonal conjugate of U.

## line-polar triangle

Let P_{i}= x_{i}: y_{i}: z_{i}, for i=1,2,3, be noncollinear points. An equation for line P_{2}P_{3}is thena where a_{1}x + b_{1}y + c_{1}z = 0,_{1}= y_{2}z_{3}- z_{2}y_{3}, and b_{1}and c_{1}are defined cyclically. The trilinear pole of this line is the point1/a This point is the A-vertex of the line-polar triangle. The B- and C- vertices are defined cyclically._{1}: 1/b_{1}: 1/c_{1}.

## major center

A major center is a triangle center X for which there exists a function f(A) such that X = f(A) : f(B) : f(C). Examples: X(1), X(2), X(3), X(4), X(6). Major centers solve certain problems in functional equations; click here (AeqMath) or here (AMM) for more.## orthojoin

Let X = x : y : z be a point, and leta

_{1}= (b^{2}+ c^{2}- a^{2})/(2bc) = cos A,

b_{1}= (c^{2}+ a^{2}- b^{2})/(2ca) = cos B,

c_{1}= (a^{2}+ b^{2}- c^{2})/(2ab) = cos C,u

_{1}= b_{1}c_{1}x^{3}- b_{1}y^{3}- c_{1}z^{3},

u_{2}= - (1 + 2c_{1}^{2})b_{1}x^{2}y - (1 + 2b_{1}^{2})c_{1}x^{2}z,

u_{3}= (2a_{1}b_{1}- c_{1})y^{2}z + (2a_{1}c_{1}- b_{1})yz^{2},

u_{4}= 3b_{1}c_{1}xy^{2}+ 3b_{1}c_{1}xz^{2},

u_{5}= (1 + b_{1}^{2}+ c_{1}^{2}- a_{1}^{2}- 4a_{1}b_{1}c_{1})xyz,f(a,b,c) = (- x + yc

_{1}+ zb_{1})(u_{1}+ u_{2}+ u_{3}+ u_{4}+ u_{5}).The orthojoin of X is the point f(a,b,c) : f(b,c,a) : f(c,a,b).

The above formula for f(a,b,c) can be written out explicitly in terms of a,b,c and simplified to the form

g(a,b,c) : g(b,c,a) : g(c,a,b), whereg(a,b,c) = bc[2abcx + c

_{3}y + b_{3}z - (a_{2}+ bc)(cy + bz)]F,where F = x[a

_{4}- (b_{2}- c_{2})_{2}] + 2a[by(b_{2}- a_{2}- c_{2}) + cz(c_{2}- b_{2}- a_{2})]The orthojoin of X, defined (6/16/03) as above, can be described geometrically (when a,b,c are sidelengths of a triangle) as the orthopole of the trilinear polar of the isogonal conjugate of X. The orthopole of a line L is constructed as follows. Let A' be the foot of the perpendicular from vertex A on L, and define B' and C' cyclically. Then the perpendiculars from A' to BC, from B' to CA, and from C' to AB concur in the orthopole of L. For a proof and link to further information, see Orthopole - a new proof by Darij Grinberg.

## orthopoint

Each point X on the line at infinity is the point common to every line in a family F(X) of pairwise parallel lines. That is, X may be regarded as the direction common to the lines in F(X). Let L be any line in F(X), and let L' be any line perpendicular to L. Let G be the family of lines parallel to L'. The orthopoint of X is the point H(X) in which L' meets the line at infinity. If X = x : y : z, thenH(X) = cy cos B - bz cos C : az cos C - cx cos A : bx cos A - ay cos B. For any X on the line at infinity, the isogonal conjugates of X and H(X) are circumcircle-antipodes; i.e., each is the X(3)-reflection of the other.

## perspective

Triangles DEF and UVW are perspective triangles if one of the following six triples of lines concur in a point:{DU,EV,FW}, {DV,EW,FU}, {DW,EU,FV}; {DU,EW,FV}, {DV,EU,FW}, {DW,EV,FU} The point of concurrence is called a

perspector(replacingcenter of perspective). If, for example, lines DU,EV,FW concur in a point, then by Desargues's theorem, the pointsEF intersect VW, FD intersect WU, DE intersect UV are collinear, and their line is the

perspectrix(replacingaxis of perspective.)In case DEF is the reference triangle, ABC, and UVW is a central triangle, it is sometimes tacitly understood that perspectivity of the two triangles refers to only one of the six possibilities, namely, the concurrence of lines DU,EV,FW. In this case, if UVW is the cevian triangle, A'B'C', of a point P, then P is the perspector of ABC and A'B'C', and the perspectrix is the trilinear polar of P.

## point

In traditional euclidean geometry,pointis not subject to definition, much as an axiom is not subject to proof. However, when (a,b,c) is variable or indeterminate, a point is defined informally by f(a,b,c) : g(a,b,c) : h(a,b,c) for all (a,b,c) for which at least one of the values f(a,b,c), g(a,b,c), h(a,b,c) is not zero. A formal definition is given in TCCT. See alsotriangle center.Three points x : y : z, r : s : t, u : v : w are collinear if and only the following determinant equation holds:

Thus, if x : y : z is a variable point, this equation gives the line determined by the points r : s : t and u : v : w.

## point-polar triangle

Let P_{i}= x_{i}: y_{i}: z_{i}, for i = 1,2,3, be noncollinear points, none lying on a sideline of ABC. The trilinear polar of P_{1}is the linex/x and the trilinear polars of P_{1}+ y/y_{1}+ z/z_{1}= 0,_{2}and P_{3}are defined cyclically. These last two lines meet in the point1/y This point is the A-vertex of the point-polar triangle. The B- and C- vertices are defined cyclically._{2}z_{3}- 1/z_{2}y_{3}: 1/z_{2}x_{3}- 1/x_{2}z_{3}: 1/x_{2}y_{3}- 1/y_{2}x_{3}.

## polar

Let W be a conic, P a point, and XX' and YY' chords of W that meet in P. As X and Y vary, the locus of the point X'Y∩XY' is a line, called the polar of P with respect to W. If W is a circumconic, it has an equation uyz + vzx + wxy = 0, and the polar of a point Q = p : q : r is the line(vr + wq)x + (wp + ur)y + (uq + vp)z = 0.

## polynomial center

A triangle center X is a polynomial center if there exists a polynomial f(a,b,c) such thatX = f(a,b,c) : f(b,c,a) : f(c,a,b). Examples: X(1), X(2), . . . , X(12), but not X(13).

## radical trace

The radical trace of two nonconcentric circles is the point of intersection of the radical axis of the circles and the line of the centers of the circles. (For examples, see X(I) for I = 6, 187, 1570, 2021-2025, 2030-2032.)

## reciprocal conjugate

Let P and U be points, neither on a sideline of ABC, given in barycentric coordinates by P = p : q : r and U = u : v : w. The P-reciprocal conjugate of U is the pointpvw : qwu : ruv. (barycentrics) As suggested by the meaning of "reciprocal",

P-reciprocal conjugate of U = G/(U-reciprocal conjugate of P), in accord with the fact that G, the centroid, is the identity corresponding to barycentric division.

The term

reciprocal conjugatewas introduced in Keith Dean and Floor van Lamoen, "Geometric construction of reciprocal conjugations,"Forum Geometricorum1 (2001) 115-120.See also

isoconjugate.

## similarity image (see homologous images)

## symbolic substitution

Let p(a, b, c), q(a, b, c), r(a, b, c) be functions of a, b, c, all of the same degree of homogeneity. As the plane consists of points [functions of the form X = x(a, b, c) : y(a, b, c) : z(a, b, c)], the substitution indicated bya ---> p(a, b, c), b--->q(a, b, c), c--->r(a, b, c) maps the set of all points - that is, the plane - into itself. Such a substitution has no clear geometric meaning, as suggested by the name,symbolicsubstitution. On the other hand, symbolic substitutions are of geometric interest because they map lines to lines, conics to conics, cubics to cubics, and they preserve incidence.Example: The symbolic substitution (a, b, c) --->(1/a, 1/b, 1/c) maps every triangle center to a triangle center, every pair of bicentric points to a pair of bicentric points, every circumconic to a circumconic, etc. However, when (a, b, c) = (2, 4, 5), for example, then a, b, c are sidelengths of a euclidean triangle, but 1/a, 1/b, 1/c are not.

Symbolic substitutions are introduced in C. Kimberling, "Symbolic substitutions in the transfigured plane of a triangle,"

Aequationes Mathematicae73 (2007) 156-171.

## syngonal image

Let P = p : q : r (barycentric coordinates) be a point not on a sideline of ABC, not X(3), and not on the circumcircle of ABC. The syngonal image of P is the point k(P) given by barycentyricsk(a,b,c,p,q,r) : k(b,c,a,q,r,p) : k(c,a,b,r,p,q),

wherek(a,b,c,p,q,r) = (q + r - p)/[2a ^{2}qr - (q + r - p)(b^{2}r + c^{2}q)].The point k(P) is the antigonal image of the anticomplement of P. For further developments, search Hyacinthos for "symgonal" - however, following Hyacinthos #9881, the spelling "syngonal" is used here.

## transcendental center

A triangle center X is a transcendental center if there exists no algebraic function f(a,b,c) such that X = f(a,b,c) : f(b,c,a) : f(c,a,b). Examples: X(359) and X(360).

## triangle center

A triangle center is a point of the form f(a,b,c) : f(b,c,a) : f(c,a,b), where f is a nonzero function satisfying two conditions:

(1) f is homogeneous in a,b,c; i.e., there is a nonnegative real number h such thatA formal definition of triangle center is given in TCCT. See alsof(ta,tb,tc) = t ^{h}f(a,b,c) for all (a,b,c) in the domain of f;(2) f is symmetric in b and c; i.e., f(a,c,b) = f(a,b,c).

polynomial center,transcendental center,central triangle,bicentric points.

## trilinear image (see homologous images)

## trilinear polar

The trilinear polar of a point p : q : r is the lineqrx + rpy + pqz = 0.

## trilinear pole

The trilinear pole of the line ux + vy + wz = 0 is the point wv : uw : uv.Geometrically, the trilinear pole of a line PU is the perspector of ABC and the vertex-triangle of the anticevian triangles of P and U. (Randy Hutson, April 9, 2016)

## unary cofactor triangle

Let P_{i}= x_{i}: y_{i}: z_{i}, for i=1,2,3, be points. The A-vertex of the unary cofactor triangle is the pointy The B-vertex and C-vertex are defined cyclically. The vertices are the isogonal conjugates of the the vertices of the line-polar triangle of the points P_{2}z_{3}- z_{2}y_{3}: z_{2}x_{3}- x_{2}z_{3}: x_{2}y_{3}- y_{2}x_{3}._{i}.If T is a triangle and U(T) its unary cofactor triangle, then U(U(T)) = T, and T and U(T) are perspective; see

eigencenter.

## vertex conjugate

The U-vertex conjugate of X is defined for distinct points U = u : v : w and X = x : y : z: (trilinears) as the point P given byP = a/[a Suppose that T = DEF and T' = D'E'F' are triangles. The vertex triangle of T and T' is the triangle V(T,T') having sidelines DD', EE', FF'. Thus, V(T,T') generalizes "perspector", since V(T,T') is a single point if and only if T is perspective to T'. If U and X are distinct points, then (vertex triangle of the circumcevian triangles of U and X) is perspective to ABC, and the perspector is the U-vertex conjugate of X, which equals the X-vertex conjugate of U. See C. Kimberling, Mappings Associated with Vertex Triangles,^{2}vwyz - ux(bw + cv)(bz + cy)] : b/[b^{2}wuzx - vy(cu + aw)(cx + az)] : c/[c^{2}uvxy - wz(av + bu)(ay + bx)].Forum Geometricorum,2 (2002) 21-32.

## waw conjugate

Let P = p : q : r and U = u : v : w be points, neither lying on a sideline of ABC. The P-waw conjugate of U is the pointh(p,q,r,u,v,w) : h(q,r,p,v,w,u) : h(r,p,q,w,u,v),

whereh(p,q,r,u,v,w) = p[x ^{2}q^{2}r^{2}+ 2p^{2}(ry - qz)^{2}- pqr^{2}xy - pq^{2}rxz]

## zayin conjugate

Let P = p : q : r and U = u : v : w be points, neither lying on a sideline of ABC. The P-zayin conjugate of U is the pointh(p,q,r,u,v,w) : h(q,r,p,v,w,u) : h(r,p,q,w,u,v),

whereh(p,q,r,u,v,w) = p(y + z) ^{2}- ry^{2}- qz^{2}+ (p - r)xy + (p - q)xz.Note that X(1)-zayin conjugacy is simply isogonal conjugacy.

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